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2w^2-11w-60=0
a = 2; b = -11; c = -60;
Δ = b2-4ac
Δ = -112-4·2·(-60)
Δ = 601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{601}}{2*2}=\frac{11-\sqrt{601}}{4} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{601}}{2*2}=\frac{11+\sqrt{601}}{4} $
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